Restore IP Addresses
A valid IP address consists of exactly four integers separated by single dots. Each integer is between 0 and 255 (inclusive) and cannot have leading zeros. Given a string s containing only digits, return all possible valid IP addresses that can be formed by inserting dots into s. You are not allowed to reorder or remove any digits in s. You may return the valid IP addresses in any order.
package questions
import _utils.UseCommentAsDocumentation
import utils.assertIterableSameInAnyOrder
/**
* A valid IP address consists of exactly four integers separated by single dots.
* Each integer is between 0 and 255 (inclusive) and cannot have leading zeros.
* Given a string s containing only digits, return all possible valid IP addresses that can be formed
* by inserting dots into s. You are not allowed to reorder or remove any digits in s.
* You may return the valid IP addresses in any order.
*
* [Source](https://leetcode.com/problems/restore-ip-addresses/)
*/
@UseCommentAsDocumentation
private fun restoreIpAddresses(s: String): List<String> {
if (s.length == 4) {
val ip = s.toCharArray().joinToString(".")
return listOf(ip)
}
// invalid ips
if (s.length < 4 || s.length > 12) {
return emptyList()
}
val result = mutableListOf<IPAddress>()
generateIPAddress(s, 0, result)
return result.mapNotNull { it.stringOrNull() }.distinct()
}
private class IPAddress {
private var address = mutableListOf<String>()
fun put(value: Char) {
if (address.isEmpty()) {
address.add(value.toString())
return
}
val last = address.last()
val newValue = last + value
if (newValue.toInt() <= 255) { // replace current field
address[address.lastIndex] = newValue
} else { // can't be accommodated into current field
address.add(value.toString())
}
}
fun putInNext(value: Char) {
address.add(value.toString())
}
fun clone(): IPAddress {
return IPAddress().let {
it.address = mutableListOf<String>().apply { this.addAll(address) }
it
}
}
fun isNoLongerValid(): Boolean {
return address.size > 4 || address.find { it.length > 1 && it.startsWith("0") } != null
}
fun stringOrNull(): String? {
if (address.size != 4) return null
if (address.find { it.length > 1 && it.startsWith("0") } != null) return null
return toString()
}
override fun toString(): String {
return address.joinToString(".") { it }
}
}
private fun generateIPAddress(s: String, index: Int, result: MutableList<IPAddress>) {
if (index > s.lastIndex) {
return
}
val character = s[index]
if (result.isEmpty()) { // add the first element
val address = IPAddress().apply { put(character) }
result.add(address)
generateIPAddress(s, index + 1, result)
return
}
val newIps = mutableListOf<IPAddress>()
result.forEach {
// when adding a new character to IP, you can either add it to currently active field
// or put it in next field
// add it to currently active field i.e. 10.1.. --2--> 10.12..
newIps.add(it.clone().apply {
this.put(character)
})
// put it in the next field i.e. 10.1.. --2--> 10.1.2.
newIps.add(it.clone().apply {
this.putInNext(character)
})
}
result.clear()
// early break. If NONE of the current ips are no longer valid, then leave the remaining characters
// as adding any other invalid will still make it invalid eg 530474625546 --> 53.0.47.46 is no longer valid
if (newIps.filter { !it.isNoLongerValid() }.isEmpty()) {
return
}
result.addAll(newIps)
generateIPAddress(s, index + 1, result)
}
fun main() {
assertIterableSameInAnyOrder(
restoreIpAddresses("530474625546"),
listOf()
)
assertIterableSameInAnyOrder(
restoreIpAddresses("103574606193"),
listOf()
)
assertIterableSameInAnyOrder(
restoreIpAddresses("255255255255"),
listOf("255.255.255.255")
)
assertIterableSameInAnyOrder(
restoreIpAddresses("25525511135"),
listOf("255.255.11.135", "255.255.111.35")
)
assertIterableSameInAnyOrder(
restoreIpAddresses("0000"),
listOf("0.0.0.0")
)
assertIterableSameInAnyOrder(
restoreIpAddresses("101023"),
listOf("1.0.10.23", "1.0.102.3", "10.1.0.23", "10.10.2.3", "101.0.2.3")
)
}
Updated on 2022-01-02