Design Hashset
Implement MyHashSet class:
void add(key)
Inserts the value key into the HashSet.bool contains(key)
Returns whether the value key exists in the HashSet or not.void remove(key)
Removes the value key in the HashSet. If key does not exist in the HashSet, do nothing.@see MyHashMap
package questions
import _utils.UseCommentAsDocumentation
/**
* Implement MyHashSet class:
* * `void add(key)` Inserts the value key into the HashSet.
* * `bool contains(key)` Returns whether the value key exists in the HashSet or not.
* * `void remove(key)` Removes the value key in the HashSet. If key does not exist in the HashSet, do nothing.
* [Source](https://leetcode.com/problems/design-hashset/)
*
* @see MyHashMap
*/
@UseCommentAsDocumentation
class MyHashSet {
private val array: Array<Node?> = Array(100) { null }
private fun getIndex(key: Int) = key % array.size
fun add(key: Int) {
val index = getIndex(key)
val (parent, self) = findParentAndSelf(index, key)
if (self == null) {
if (parent == null) {
array[index] = Node(key)
} else {
parent.next = Node(key)
}
}
}
private fun findParentAndSelf(index: Int, key: Int): Pair<Node?, Node?> {
var current: Node? = array[index] ?: return null to null
if (current?.key == key) { // first item has the key
return null to current // so no parents
}
while (current != null) {
if (current.next?.key == key) { // next item has the key
return current to current.next
}
if (current.next == null) { // next item is null so last most item is the parent
return current to null
}
current = current.next
}
return current to null
}
fun remove(key: Int) {
val index = getIndex(key)
val (parent, self) = findParentAndSelf(index, key)
if (self != null) {
if (parent == null) {
array[index] = self.next
} else {
parent.next = self.next
}
}
}
fun contains(key: Int): Boolean {
val index = getIndex(key)
val (_, self) = findParentAndSelf(index, key)
return self != null
}
inner class Node(val key: Int) {
var next: Node? = null
}
}
fun main() {
run {
val myHashSet = MyHashSet()
myHashSet.add(1) // set = [1]
myHashSet.add(2) // set = [1, 2]
myHashSet.contains(1) // return True
myHashSet.contains(3) // return False, (not found)
myHashSet.add(2) // set = [1, 2]
myHashSet.contains(2) // return True
myHashSet.remove(2) // set = [1]
myHashSet.contains(2) // return False, (already removed)
}
}
Updated on 2021-11-07