Length Of Longest Increasing Sub Seq
Given an integer array nums, return the length of the longest strictly increasing subsequence. A subsequence is a sequence that can be derived from an array by deleting some or no elements without changing the order of the remaining elements.
@see LongestIncreasingSubSeq
package questions
import _utils.UseCommentAsDocumentation
import utils.shouldBe
/**
* Given an integer array nums, return the length of the longest strictly increasing subsequence.
* A subsequence is a sequence that can be derived from an array by deleting some or no elements
* without changing the order of the remaining elements.
*
* [Source](https://leetcode.com/problems/longest-increasing-subsequence/) | [Explanation](https://www.youtube.com/watch?v=mouCn3CFpgg)
*
* @see LongestIncreasingSubSeq
*/
@UseCommentAsDocumentation
private object LengthOfLongestIncreasingSubSeq
private fun lengthOfLIS(nums: IntArray): Int {
if (nums.size == 1) return 1
var maxSubsequenceSize = 1
val increasingSeq = IntArray(nums.size) { 1 }
for (i in 1..nums.lastIndex) {
for (j in 0 until i) {
// (Is still increasing?) && (choose the best i.e. larger answer)
if (nums[i] > nums[j] && increasingSeq[i] <= increasingSeq[j]) {
increasingSeq[i] = 1 + increasingSeq[j]
}
}
maxSubsequenceSize = maxOf(maxSubsequenceSize, increasingSeq[i])
}
return maxSubsequenceSize
}
fun main() {
val solutionFns: List<(IntArray) -> Int> = listOf(::lengthOfLIS)
for (fn in solutionFns) {
fn(intArrayOf(5, 8, 7, 1, 9)) shouldBe 3
fn(intArrayOf(10, 9, 2, 5, 3, 7, 101, 18)) shouldBe 4
fn(intArrayOf(0, 1, 0, 3, 2, 3)) shouldBe 4
fn(intArrayOf(7, 7, 7, 7, 7, 7, 7)) shouldBe 1
fn((10 downTo 1).toList().toIntArray()) shouldBe 1
}
}
Updated on 2021-11-16