Reorder List
You are given the head of a singly linked-list. The list can be represented as L0 → L1 → … → Ln - 1 → Ln
Reorder the list to be on the following form: L0 → Ln → L1 → Ln - 1 → L2 → Ln - 2 → …
You may not modify the values in the list's nodes. Only nodes themselves may be changed.
package questions
import questions.common.LeetNode
import utils.assertIterableSame
import java.util.*
/**
* You are given the head of a singly linked-list. The list can be represented as `L0 → L1 → … → Ln - 1 → Ln`
*
* Reorder the list to be on the following form: `L0 → Ln → L1 → Ln - 1 → L2 → Ln - 2 → …`
* You may not modify the values in the list's nodes. Only nodes themselves may be changed.
*
* [Source](https://leetcode.com/problems/reorder-list)
*/
private fun reorderList(head: LeetNode?) {
if (head == null) return
if (head.next == null) return
val stack = LinkedList<LeetNode>()
var current: LeetNode? = head
while (current != null) {
stack.addLast(current) // add the nodes to a stack
current = current.next
}
val lengthToSwapsRequired = mapOf(
1 to 0, 2 to 0, // if there are 1 or 2 items, no swaps required
3 to 1, 4 to 1, // if there are 3 or 4 items, just 1 swap required
5 to 2, 6 to 2, // if there are 5 or 6 items, just 2 swap required
7 to 3, 8 to 3,
9 to 4, // case for 9 or 10 items (10 is not possible, but if totalLength=0,
10 to 4, // ...it can be safely considered that the items is in multiple of 10
)
fun numberOfSwapsRequired(totalLength: Int): Int {
if (totalLength <= 10) {
return lengthToSwapsRequired[totalLength]!!
}
// From my observation, the behavior of totalLength to swaps required is:
//
// Length | swaps
// * 1 -> 0
// * 2 -> 0
// * 9 -> 4
// * 10 -> 4
// * 11 -> 5 ( lengthToSwapsRequired[10] + lengthToSwapsRequired[11 % 10] = 4 ) + 1
// * 12 -> 5 ( lengthToSwapsRequired[10] + lengthToSwapsRequired[12 % 10] = 4 ) + 1
// * 13 -> 6 ( lengthToSwapsRequired[10] + lengthToSwapsRequired[13 % 10] = 5 ) + 1
// * 20 -> 9
// * 21 -> 10
// extra 1 for every 10
// each 10s adds a 4
// each 10s adds a 1
// subtract 10 from it and do it again
return 4 + 1 + numberOfSwapsRequired(totalLength - 10)
}
val totalSwapsRequired = numberOfSwapsRequired(stack.size)
var previous: LeetNode? = head
current = head.next
var swapsDone = 0
while (current != null) {
val toBeInserted =
stack.removeLastOrNull() ?: break // pop the stack to put it in the middle of prev and current
swapsDone++
// place [toBeInserted] in the middle
previous?.next = toBeInserted
toBeInserted.next = current
// move to next insertion point
previous = toBeInserted.next
current = previous?.next
if (swapsDone > totalSwapsRequired) {
// no more required
current?.next = null // nullify the end
break
}
}
}
fun main() {
run {
val input = LeetNode.from(IntRange(1, 49).toList().toIntArray())
reorderList(input)
assertIterableSame(
actual = input.toList(),
expected = LeetNode.from(
1,
49,
2,
48,
3,
47,
4,
46,
5,
45,
6,
44,
7,
43,
8,
42,
9,
41,
10,
40,
11,
39,
12,
38,
13,
37,
14,
36,
15,
35,
16,
34,
17,
33,
18,
32,
19,
31,
20,
30,
21,
29,
22,
28,
23,
27,
24,
26,
25
).toList()
)
}
run {
val input = LeetNode.from(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11)
reorderList(input)
assertIterableSame(
actual = input.toList(),
expected = LeetNode.from(1, 11, 2, 10, 3, 9, 4, 8, 5, 7, 6).toList()
)
}
run {
val input = LeetNode.from(1, 2, 3, 4)
reorderList(input)
assertIterableSame(
actual = input.toList(),
expected = LeetNode.from(1, 4, 2, 3).toList()
)
}
run {
val input = LeetNode.from(1, 2, 3, 4, 5)
reorderList(input)
assertIterableSame(
actual = input.toList(),
expected = LeetNode.from(1, 5, 2, 4, 3).toList()
)
}
}
Updated on 2022-08-24