Reshape The Matrix
You are given an m x n
matrix mat
and two integers r
and c
representing the number of rows and the number of columns of the wanted reshaped matrix.
The reshaped matrix should be filled with all the elements of the original matrix
in the same row-traversing order as they were.
If the reshape operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.
package questions
import _utils.UseCommentAsDocumentation
import utils.shouldBe
/**
* You are given an `m x n` matrix `mat` and two integers `r` and `c`
* representing the number of rows and the number of columns of the wanted reshaped matrix.
* The reshaped matrix should be filled with all the elements of the original matrix
* in the same row-traversing order as they were.
*
* If the reshape operation with given parameters is possible and legal, output the new reshaped matrix;
* Otherwise, output the original matrix.
*
* [Source](https://leetcode.com/problems/reshape-the-matrix/)
*/
@UseCommentAsDocumentation
private fun matrixReshape(mat: Array<IntArray>, r: Int, c: Int): Array<IntArray> {
val col = mat[0].size
val row = mat.size
if (r * c != col * row) {
return mat
}
val result = Array<IntArray>(r) { IntArray(c) { -1 } }
var rowIndex = 0
var colIndex = 0
for (i in 0 until row) {
for (j in 0 until col) {
if (colIndex >= c) {
rowIndex++
colIndex = 0
}
result[rowIndex][colIndex] = mat[i][j]
colIndex++
}
}
return result
}
fun main() {
run() {
val result = matrixReshape(mat = arrayOf(intArrayOf(1, 2), intArrayOf(3, 4)), r = 1, c = 4)
val expected = arrayOf(intArrayOf(1, 2, 3, 4))
result.forEachIndexed { index, ints ->
ints shouldBe expected[index]
}
}
run {
val result = matrixReshape(
mat = arrayOf(
intArrayOf(1, 2),
intArrayOf(3, 4)
), r = 2, c = 4
)
val expected = arrayOf(
intArrayOf(1, 2),
intArrayOf(3, 4)
)
result.forEachIndexed { index, ints ->
ints shouldBe expected[index]
}
}
}
Updated on 2021-11-06