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Format Phone Number

Given a phone number should format in the form of abc-def-ijk. Last two part can be of 2 digits

package questions

/**
* Given a phone number should format in the form of abc-def-ijk. Last two part can be of 2 digits
*/
fun main() {
solution("00-44 48 5555 83612").also { println(it) }
solution("00-44 48 5555 8361").also { println(it) }
solution("00-44 48 5555 836122").also { println(it) }
solution("00-44 48 5555").also { println(it) }
solution("00-4").also { println(it) }
solution("00").also { println(it) }
solution("0 0 ").also { println(it) }
}

fun solution(S: String): String {
val digits = S.toCharArray().filter { Character.isDigit(it) }
if (digits.size < 3) {
return digits.joinToString("")
}
val remainder = digits.size % 3
if (remainder == 0) {
return formatPhoneNumber(digits).toString()
} else {
val division = digits.size / 3
if (remainder == 2) {
val numberOfItemsToTake = division * 3
val formattableTo3digits = digits.subList(0, numberOfItemsToTake)
return formatPhoneNumber(formattableTo3digits)
.append("-")
.append(digits[numberOfItemsToTake])
.append(digits[numberOfItemsToTake + 1]).toString()
} else {
val numberOfItemsToTake = (division - 1) * 3
val formattableTo3digits = digits.subList(0, numberOfItemsToTake)
return formatPhoneNumber(formattableTo3digits)
.append("-")
.append(digits[numberOfItemsToTake + 0])
.append(digits[numberOfItemsToTake + 1])
.append("-")
.append(digits[numberOfItemsToTake + 2])
.append(digits[numberOfItemsToTake + 3])
.toString()
}
}
}

fun formatPhoneNumber(digits: List<Char>): StringBuilder {
val sb = StringBuilder()
digits.forEachIndexed { index, c ->
sb.append(c)
if ((index + 1) % 3 == 0 && index < digits.lastIndex) {
sb.append("-")
}
}
return sb
}


Updated on 2021-02-03